“…It is known that det(zI − A(z)) has simple zeros at 1 and and m − 1 zeros (counting multiplicities) in the open unit disk, furthermore, it has no other zeros on {z ∈ C : 1 Յ |z| Յ , z 1, z }. By similar arguments as in Section 2.2 of [13], we have that (zI −Â(z))(zI − A(z)) −1 has a removable singularity at z = 1 and that (zI −Â(z))(zI − A(z)) −1 has a simple pole at z = . Furthermore, by the same procedure as in the proof of Lemma 3 in [12], we can see that the power series ∞ n=0 p n z n has radius of convergence .…”