2003
DOI: 10.1007/s10582-003-0101-0
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Synthesis and spectra of N-15 labelled phenylazides

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Cited by 14 publications
(19 citation statements)
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“…Asymmetric azide stretching is usually observed at wavenumbers between 2080 cm −1 and 2170 cm −1 , and we therefore assign the band at 2114 cm −1 to the azide moiety. The structure of the band is attributed to a Fermi resonance 10. Carbonyl stretching of the carboxylate moiety is expected between 1705 cm −1 and 1730 cm −1 ; carbonyl stretching of the carbamate moiety (amide I) is expected between 1705 cm −1 and 1722 cm −1 9.…”
mentioning
confidence: 90%
“…Asymmetric azide stretching is usually observed at wavenumbers between 2080 cm −1 and 2170 cm −1 , and we therefore assign the band at 2114 cm −1 to the azide moiety. The structure of the band is attributed to a Fermi resonance 10. Carbonyl stretching of the carboxylate moiety is expected between 1705 cm −1 and 1730 cm −1 ; carbonyl stretching of the carbamate moiety (amide I) is expected between 1705 cm −1 and 1722 cm −1 9.…”
mentioning
confidence: 90%
“…However, this accuracy in 15 N CS calculations is completely unacceptable for investigations of triazides 1–7 , in which the N α , N β and N γ atoms of nonequivalent azido groups display quite similar 15 N CS . To test the performance of different DFT approaches to calculations of 15 N CS in azides, azidobenzene 8 , diazidotoluene 9 and cyanuryltriazide 10 with 15 N NMR spectra described in the literature were chosen as model systems. The most suitable DFT approach was then used for the assignment of 15 N CS in triazides 1–7 .…”
Section: Introductionmentioning
confidence: 99%
“…into dinitrogen and a mesityl radical . To test our hypothesis that 5 is formed by γ‐N abstraction from MesN 3 , we reacted 1 with terminally 15 N‐labeled mesityl azide, MesNN 15 N, which was synthesized following a procedure analogous to that used by Lešetický to synthesize PhNN 15 N . To determine whether the reaction of 1 with MesNN 15 N in THF produced ( tbs L)Cr 3 ( μ 3 ‐ 15 N) ( 5‐ 15 N ), the product of the reaction was decomposed using HCl to produce ammonium chloride and then treated with base to liberate ammonia, which was vacuum transferred into a solution of HCl in diethyl ether.…”
Section: Figurementioning
confidence: 99%