“…& 3 that the increase of elastic modulus of sample A is slower than those of sample B, and the decrease of tanδ of sample A is slower than those of sample B in low frequency phase, respectively. In the entire scanning process, the elastic modulus of sample B is bigger than that of the sample A, but the tanδ of former is smaller, which shows that the molecular weight distribution of sample A is wide [6], the result has been showed in reference [3]. It can be held that the molecule of the sample B is bigger [3], the number of the internal rotation molecular chain conformation correspondingly increase, lead to the increase of molecular chains flexibility, the bigger the molecular weight, the longer the molecular chain, and thus, there are much more tangles among molecular chains (this is why sample B has bigger crosslink density compared with those of sample A ) to prevent the slide among molecular chain, and help improve elasticity [5].…”