1990
DOI: 10.1112/blms/22.6.576
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Symmetries of Julia Sets

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Cited by 56 publications
(49 citation statements)
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“…Then for all f,g G G, we may write [/, g] = <f>i ° ... ° <f> n for some elements <f>\,...,<f> n ofQ?.ln other words, Notice that in Theorem 4.3, the group H is a subgroup of the conformal automorphism group of J(G). Finally in this section we wish to point out the following result, largely contained in A. Beardon's work[2,3].…”
mentioning
confidence: 91%
“…Then for all f,g G G, we may write [/, g] = <f>i ° ... ° <f> n for some elements <f>\,...,<f> n ofQ?.ln other words, Notice that in Theorem 4.3, the group H is a subgroup of the conformal automorphism group of J(G). Finally in this section we wish to point out the following result, largely contained in A. Beardon's work[2,3].…”
mentioning
confidence: 91%
“…In particular, the critical point c i has finite orbit for f t if and only if c j has finite orbit for f t . If deg z h = 1, then h t must be a symmetry of the Julia set of f t ; these were classified in [Be1]. If deg z h > 1, then h t must share an iterate with f t for all t [Ri2]; it follows that condition (4) is symmetric in i and j.…”
mentioning
confidence: 99%
“…For a polynomial f ∈ C[X], we let J(f ) denote the Julia set of f (see [Bea91, Chapter 3] or [Mil99] for the definition of a Julia set of a rational function over the complex numbers). As proved by Beardon [Bea90,Bea92], any family of polynomials which have the same Julia set J is determined by the symmetries of J . , which we will use later.…”
Section: Symmetries Of the Julia Setmentioning
confidence: 99%