High Performance Liquid Chromatography 1996
DOI: 10.1007/978-94-011-0597-2_4
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“…(1) with x 1 and x 2 being the volume fractions and P 1 ′ and P 2 ′ being the polarity indices of the solvents (5.1, 4.3, and 10.2 for MeOH, EtOH, and water, respectively). 88,90 On the basis of this formula, Figure 4b was constructed and depicts the degree of delignification as a function of polarity P′. The amount of lignin extracted from the biomass follows a parabolic curve, with a maximum for P′ ≈ 8.…”
Section: ■ Results and Discussionmentioning
confidence: 64%
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“…(1) with x 1 and x 2 being the volume fractions and P 1 ′ and P 2 ′ being the polarity indices of the solvents (5.1, 4.3, and 10.2 for MeOH, EtOH, and water, respectively). 88,90 On the basis of this formula, Figure 4b was constructed and depicts the degree of delignification as a function of polarity P′. The amount of lignin extracted from the biomass follows a parabolic curve, with a maximum for P′ ≈ 8.…”
Section: ■ Results and Discussionmentioning
confidence: 64%
“…A quantitative method, earlier proposed by Snyder, to express relative solvent polarity is based on an experimentally determined polarity index P ′ . The polarity of a solvent mixture is given by the following formula with x 1 and x 2 being the volume fractions and P 1 ′ and P 2 ′ being the polarity indices of the solvents (5.1, 4.3, and 10.2 for MeOH, EtOH, and water, respectively). , On the basis of this formula, Figure b was constructed and depicts the degree of delignification as a function of polarity P ′.…”
Section: Resultsmentioning
confidence: 99%
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