2004
DOI: 10.1016/j.jalgebra.2003.08.017
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Supplement submodules and a generalization of projective modules

M.C. Izurdiaga

Abstract: Let R be a ring with Jacobson radical J (R). Given a left R-module M, a supplement submodule of M is a submodule K M for which there exists K ≤ M such M = K + K and K is minimal with respect to this property. In general, supplement submodules are strict generalizations of direct summands. Those rings for which every supplement submodule of a finitely generated projective module is a direct summand have been widely treated in the literature (see [6][7][8]11,13,16]). However, it is an open problem to give an int… Show more

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Cited by 10 publications
(3 citation statements)
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“…Suppose that U is a uniserial module. Then the endomorphism ring E = End R (U ) has two (two sided) ideals L = {f ∈ E : f is not injective} and K = {f ∈ E : f is not surjective} such that every proper right ideal of E is contained either in L or in K (see [11,Proposition 3.7] and [7,Theorem 1.2]). Now we give the following example which is important in terms of existing of an H-supplemented module that does not satisfy FIEP.…”
Section: Dual Square Free Modulesmentioning
confidence: 99%
“…Suppose that U is a uniserial module. Then the endomorphism ring E = End R (U ) has two (two sided) ideals L = {f ∈ E : f is not injective} and K = {f ∈ E : f is not surjective} such that every proper right ideal of E is contained either in L or in K (see [11,Proposition 3.7] and [7,Theorem 1.2]). Now we give the following example which is important in terms of existing of an H-supplemented module that does not satisfy FIEP.…”
Section: Dual Square Free Modulesmentioning
confidence: 99%
“…A is said to be radical B -projective if, for any module X , any homomorphism f : A → X , and any epimorphism g : B → X , there exists a homomorphism h : A → B such that Im (f − gh) ≪ X (cf. [11,16]), and equivalently, for any epimorphism g : B → X and any homomorphism f : A → X , there exist a small epimorphism ρ : X → Y for some module Y , a homomorphism h : A → B such that ρgh = ρf ([17, Proposition 1.2]). A is said to be im-summand (im-coclosed, im-small, resp.)…”
Section: Preliminariesmentioning
confidence: 99%
“…By [13,Theorem 1.6], there exist 0 = x ∈ R and r 0 ∈ R such that K = x R and x 2 r 0 = x. Then x(xr 0 − 1) = 0.…”
Section: Proposition 48 Let R Be a Domain Then R R Is An S-coretracmentioning
confidence: 99%