2005
DOI: 10.1051/jp4:2005123015
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Superconductivity and ferromagnetism in BM5Se9(B = Al, Ga, Ge, Sn, Sb; M = V, Nb, Ta)

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“…Se 9 , SbNb 5 Se 9 Ga 0.84 Sn 0.15 Nb 5 Se 9 etc [2,3]. without any V atoms, the AC and DC susceptibilities being in good agreement.…”
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confidence: 68%
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“…Se 9 , SbNb 5 Se 9 Ga 0.84 Sn 0.15 Nb 5 Se 9 etc [2,3]. without any V atoms, the AC and DC susceptibilities being in good agreement.…”
mentioning
confidence: 68%
“…Using different A15/MSe 2 (or A 3 B/MSe 2 ) couples, have been therefore explored several (B/B')(M/A) 5 Se 9 systems where {A=M= (Nb, V, Ta); B=B'= (Al, Ge, Ga, Sn, Sb)}, according to the process which lead to get SnNb 5 Se 9 . It was shown [2,3] that the presence of Vanadium plays a determinant role in the physical properties: as in 1T-VSe 2 where V excess causes a weak paramagnetism [4], in phases with vanadium, couplings are ferromagnet ones, but phases without any V are superconductors: for examples, as SnNb 0.5 Ta 4.5 Se 9 and SnNb 5 Se 9 themselves, GaNb 5 Se 9 , Ga 0.84 Sn 0.15 Nb 5 Se 9 are superconductor but, as GaV 5 Se 9 itself, GaV 0.15 Ta 4.85 Se 9 and Sn 0.94 Ga 0.05 Nb 4.70 V 0.30 Se 9 are ferromagnet [2,3]. So when some vanadium atoms enter in the frame, electronic repulsions appear which destroy the supercon-ductivity state and replace it by ferromagnetic couplings.…”
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confidence: 98%
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