1982
DOI: 10.1109/tit.1982.1056480
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Sufficient conditions for uniqueness of a locally optimal quantizer for a class of convex error weighting functions

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Cited by 121 publications
(83 citation statements)
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“…Similarly, Figure 7 demonstrates the existence of multiple mixture model solutions for a two dimensional distribution using the population-based EM algorithm. In 1-dimension, there will often be a unique set of k self-consistent points (Trushkin, 1982;Li and Flury, 1995;Tarpey, 1994;Mease and Nair, 2006), for instance if the density is log-concave. It would be interesting to determine if conditions exist that guarantee the existence of a unique set of (non-degenerate) solutions for the population-based EM algorithm.…”
Section: Population-basedmentioning
confidence: 99%
“…Similarly, Figure 7 demonstrates the existence of multiple mixture model solutions for a two dimensional distribution using the population-based EM algorithm. In 1-dimension, there will often be a unique set of k self-consistent points (Trushkin, 1982;Li and Flury, 1995;Tarpey, 1994;Mease and Nair, 2006), for instance if the density is log-concave. It would be interesting to determine if conditions exist that guarantee the existence of a unique set of (non-degenerate) solutions for the population-based EM algorithm.…”
Section: Population-basedmentioning
confidence: 99%
“…For some special cases involving normal distributions see Gray and Karnin (1982) and Baubkus (1985). On the other hand, in the one-dimensional case, uniqueness holds, e.g., if log f (x) is concave (Fleischer 1964, Trushkin 1982, Kieffer 1983. The corresponding solution for the normal distribution may be found in Ogawa (1951Ogawa ( , 1962, Cox (1957), or Bock (1974.f).…”
Section: The Asymptotic Distribution Of the Test Statistics G~ And K~mentioning
confidence: 99%
“…This assumption has been discussed very often in the k-means literature (see, for instance, [2]). Some results are known in the case that E = IR and α = 0 (see, for instance, [13], [8], [5], [14], and [9]), but, at our best acknowledge, yet there is no satisfactory result even in the case E = IR 2 , k = 2 and α = 0.…”
Section: Remark 36mentioning
confidence: 79%