Let U 5 be the tournament with vertices v 1 , . . . , v 5 such that v 2 → v 1 , and v i → v j if j − i ≡ 1, 2 (mod 5) and {i, j} = {1, 2}. In this paper we describe the tournaments which do not have U 5 as a subtournament. Specifically, we show that if a tournament G is "prime"-that is, if there is no subset X ⊆ V (G), 1 < |X| < |V (G)|, such that for all v ∈ V (G) \ X, either v → x for all x ∈ X or x → v for all x ∈ X-then G is U 5 -free if and only if either G is a specific tournament T n or V (G) can be partitioned into sets X, Y , Z such that X ∪ Y , Y ∪ Z, and Z ∪ X are transitive. From the prime U 5 -free tournaments we can construct all the U 5 -free tournaments. We use the theorem to show that every U 5 -free tournament with n vertices has a transitive subtournament with at least n log 3 2 vertices, and that this bound is tight.