“…Indeed, take W 1 = span{(1, 0, 0)}, W 2 = span{(1, 1, 0)}, W 3 = span{(0, 1, 0)}, W 4 = span{(0, 0, 1)}, and ω 1 = ω 3 = ω 4 = 1, ω 2 = √ 2. Then W = {(W i , ω i )} i∈I is a fusion frame for R 3 with an alternate dual as V = {(V i , υ i )} i∈I where V 1 = span{(0, 1, 0)}, V 2 = R 3 , V 3 = span{(1, 0, 0)}, V 4 = span{(0, 0, 1)}, and υ 1 = υ 3 = 3 , υ 2 = 3 √ 2, υ 4 = 1; see Example 3.1 of [1]. A straightforward calculation shows that W is not an alternate dual fusion frame of V .…”