“…Now (α 1 , β 1 , γ 1 , δ 1 ) = (3, −1, −2, 1), (α 2 , β 2 , γ 2 , δ 2 ) = (4, 1, 3, 1), and (α 3 , β 3 , γ 3 , δ 3 ) = (2n, 1, 2n − 1, 1). Let (λ 1 , µ 1 ) = (3, −1), (λ 2 , µ 2 ) = (4, 1), and (λ 3 , µ 3 ) = (12,1). Then λ = 12, the genus of the pseudo-horizontal surface is…”