1983
DOI: 10.1007/bf01978662
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Strongly imbedded infinitely isolated subgroup of a periodic group

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Cited by 3 publications
(3 citation statements)
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“…As shown in [2], O~S~ is finite since ~BCS~ + { ; from here and from the theorem of [2] we obtain a contradiction with the existence of the element $ . As shown in [2], O~S~ is finite since ~BCS~ + { ; from here and from the theorem of [2] we obtain a contradiction with the existence of the element $ .…”
supporting
confidence: 56%
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“…As shown in [2], O~S~ is finite since ~BCS~ + { ; from here and from the theorem of [2] we obtain a contradiction with the existence of the element $ . As shown in [2], O~S~ is finite since ~BCS~ + { ; from here and from the theorem of [2] we obtain a contradiction with the existence of the element $ .…”
supporting
confidence: 56%
“…By Lemma 2.1, M~4=~ and, consequently, N is strongly imbedded in K. By Lemma 2.6, K is a finite subgroup; therefore, if N contains more than one involution, then, by the theorem from[2], ~ satisfies the assertion ofTheorem 2.2, in spite of our assumption. Obviously, L~_-gr(~'~d'~-'c"]~L c andl/tl= ILJ; ¢ The lemma is proved.consequently, 0J e N~L ~ .As the fundamental step of the proof, we show that ~ satisfies the assertion of Theorem 2.2.…”
mentioning
confidence: 88%
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