2002
DOI: 10.1016/s0022-4049(02)00016-6
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Strong hypergroups of order three

Abstract: This paper investigates the question of when a finite hypergroup with three elements is strong, that is satisfies the condition that its dual signed hypergroup is actually a hypergroup. We classify hermitian hypergroups of order three by weight into two dimensional families and show that the algebraic conditions arising from duality yield four interesting curves in the plane which bound the character values of strong and non strong hypergroups. By analysing the relations between these curves we discover that t… Show more

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Cited by 12 publications
(6 citation statements)
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References 14 publications
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“…From this fact, all hypergroups of order less than three are commutative. As was shown in [19], all hypergroups of order three are commutative. We next prove that all hypergroups of order four are commutative.…”
Section: Introductionmentioning
confidence: 78%
See 1 more Smart Citation
“…From this fact, all hypergroups of order less than three are commutative. As was shown in [19], all hypergroups of order three are commutative. We next prove that all hypergroups of order four are commutative.…”
Section: Introductionmentioning
confidence: 78%
“…The structure of hypergroups has been studied by many authors (see [1-16, 18, 19] and references therein). N. J. Wildberger [19] determined the structure of hypergroups of order three; however the structure of hypergroups of order greater than three has not been determined. R. Ichihara and S. Kawakami [6] revealed the structure of hypergroups of order four which has a subhypergroup.…”
Section: Introductionmentioning
confidence: 99%
“…Remark 4.3. According to [12,Section 4], the pre-hypergroup H = {c 0 , c 1 , c 2 } with the structure…”
Section: The Case Of Diameter Twomentioning
confidence: 99%
“…As was the case with groups, we can completely determine structures of hypergroups of low order. Structures of finite hypergroups of low orders have been studied in [18] and [15] for examples. In this paper, we shall treat hermitian discrete hypergroups which are generalizations of Z/2Z.…”
Section: Introductionmentioning
confidence: 99%