“…The solution to the whole system (23) becomes φ = (0, 0, 0, 0) and ψ = σ 3 ψ 3 + σ 4 ψ 4 , where ψ 3 = (− √ γ − 1, 0, 0, 1) and ψ 4 = (0, iωū, s, 0) . Finally, the homogeneous solution to (20) is Ŵh = ΨK(x) σ, where Ψ = [ψ 1 , ψ 2 , ψ 3 , ψ 4 ], K(x) = diag(e κ 1 , e κ 2 , e κ 3 , e κ 3 ) and σ = (σ 1 , σ 2 , σ 3 , σ 4 ) contain the solution vectors, the exponential functions and the parameters that will be determined from the boundary conditions, respectively.…”