“…|x(s)| 8+e s +s 2 ) ds, t ∈ (0, 1] ∪(2,3],x(t) = x(t) (3+t 2 )(1+|x(t)|) , t ∈ (1, 2], |y(s)| 8+e s +s 2 ) ds| ≤ e t , t ∈ (0, 1] ∪ (2, 3], |y(t) -y(t) (3+t 2 )(1+|x(t)|) | ≤ 1, t ∈ (1, 2]. Let J = [0, 3], α = β =1 2 , r = 1 3 , = -2.70, θ =5 6 , p =4 3 , η = 1 4 and 0 = t0 < s 0 = 1 < t 1 = 2 < s 1 = τ = 3.…”