Spin-dependent studies of the dynamics of He(23S) atom deexcitation at surfaces

Electron Spectroscopy Using Metastable Atoms as Probes for Solid Surfaces

“…127 Although the copper is nonmagnetic, the polarization P was found to be nonzero, i.e., it is about 20% at the lower kinetic energy region and rises up to about 75% at the highest energy region (corresponding to emission from E F ). Some interpretations of this spin correlation involving the surface electronic properties were given by Dunning et al 51,128,148,149 and Salmi et al 140…”

“…Recently MAES using spin-polarized metastable atoms has been developed by Dunning and his collaborators, who named the method SPMDS (spin-polarized metastable-atom deexcitation spectroscopy) . Their apparatus is shown in Figure …”

“…Recently MAES using spin-polarized metastable atoms has been developed by Dunning and his collaborators, who named the method SPMDS (spinpolarized metastable-atom deexcitation spectroscopy). 51 Their apparatus is shown in Figure 3. 52 A ground-state helium beam formed by a multichannel array is partly excited to the 2 1 S and 2 3 S states by a coaxial electron gun, which utilizes a solenoid to focus impact electrons.…”

Organic mass spectrometry and control of fragmentation using a fast flow glow discharge ion source

“…Measurements of the relative ion kinetic energies27 are consistent with fragmentation by electron bombardment in a secondary discharge close to the ion exit cone surface. Electrons can be released at the cone surface by ion bombardment (minor pathway) and by Auger processes36–38 of excited states of the argon discharge gas. These electrons are accelerated back into the plasma, away from the negatively biased cone surface.…”

Spin Polarized MetastableHe*(23S,1s2<

“…In this context, the comparison between the spin polarization asymmetries of surface bands and H 1 MSD is expected to enable revelation of the electronic transition process in MSD. In other words, the spin polarization asymmetry for each surface band obtained by SPMDS acts as a label [11], and, by the interpretation of the combination of these labels to fit the asymmetry of the H 1 MSD, the electronic transition process may be derived. The present results are discussed with respect to this interpretation, and it is indicated that the neutralization of the hole created in the OH 3s orbital by the Na 3s electrons plays an important role in the H 1 MSD yield.…”