2000
DOI: 10.1017/s0017089500010119
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Sphere theorem by means of the ratio of mean curvature functions

Abstract: Abstract. It is well known that a compact embedded hypersurface of the Euclidean space without boundary is a round sphere if one of mean curvature functions is constant. In this note, we show that a compact embedded hypersurface of the Euclidean space (and other constant curvature spaces) without boundary is a round sphere if the ratio of some two mean curvature functions is constant.

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Cited by 20 publications
(16 citation statements)
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“…Theorem 2 contains the case where H k H l = η(r) for some monotone decreasing function η and k > l. We notice that the same result also applies to the space forms R n , H n and S n + (open hemisphere) without the star-shapedness assumption (Theorem 7). Our result extends [20,Theorem B] We next prove, in Section 4, a rigidity theorem for self-expanding solitons to the weighted generalized inverse curvature flow in Euclidean space R n≥3 :…”
Section: Motivation and Main Resultssupporting
confidence: 53%
“…Theorem 2 contains the case where H k H l = η(r) for some monotone decreasing function η and k > l. We notice that the same result also applies to the space forms R n , H n and S n + (open hemisphere) without the star-shapedness assumption (Theorem 7). Our result extends [20,Theorem B] We next prove, in Section 4, a rigidity theorem for self-expanding solitons to the weighted generalized inverse curvature flow in Euclidean space R n≥3 :…”
Section: Motivation and Main Resultssupporting
confidence: 53%
“…Related to this, Koh [22] has recently proved the same kind of result under the hypothesis that the ratio H s /H r is constant, 1 r < s n.…”
Section: (I) Ifc 0 Then M Is a Leaf Of The Foliation F(k)mentioning
confidence: 64%
“…For Theorem A in [1] is not true in this case as Wente's disproving the Hopf's conjecture [3] shows. In this note, however, we prove the theorem above for an immersion by slightly changing the argument of [1]. Theorem 2.…”
mentioning
confidence: 95%
“…As H 0 is defined to be 1, H k =H 0 ¼ H k . Thus, if H k =H 0 is constant, the theorem above does not hold for the same reason that the proof of [1] does not apply directly. The first-named author would like to thank the referee of [1] for suggesting Theorem 2.…”
mentioning
confidence: 98%
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