“…Let f{x,y) = x 2 + (x 4 -x 2 )y, so thatp(a:) = x 1 and q(x) = x 4 -i 2 ; the conditions of Theorem 1.1 are satisfied as is easily checked, so IZf is a radical class. It is easy to see that all zerorings are in 11 f, which is therefore semiprime, so if it were (p; g)-regular for some p, q, then it would contain J (by [4,Theorem 3]). However, R -Z 0 \X]/(X 3 ) is nil and not in 1Z f , since (writing li for the image of X in R), there would need to be a P(X) € R such that X -X P(X) = 0, which there is not.…”