2019
DOI: 10.1049/iet-spr.2018.5056
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Sparse non‐negative signal reconstruction using fraction function penalty

Abstract: Many practical problems in the real world can be formulated as the non-negative ℓ 0-minimisation problems, which seek the sparsest non-negative signals to underdetermined linear equations. They have been widely applied in signal and image processing, machine learning, pattern recognition and computer vision. Unfortunately, this non-negative ℓ 0-minimisation problem is non-deterministic polynomial hard (NP-hard) because of the discrete and discontinuous nature of the ℓ 0-norm. Inspired by the good performances … Show more

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Cited by 1 publication
(2 citation statements)
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“…, a > 0 is called the fraction function. In addition, the fraction function is also used to the matrix rank minimization problem [7,8] and sparse nonnegative signal recovery [9]. It is easy to verify that p a (t ) = 0 if t = 0 and lim a→+∞ p a (t ) = 1 if t = 0.…”
Section: Introductionmentioning
confidence: 99%
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“…, a > 0 is called the fraction function. In addition, the fraction function is also used to the matrix rank minimization problem [7,8] and sparse nonnegative signal recovery [9]. It is easy to verify that p a (t ) = 0 if t = 0 and lim a→+∞ p a (t ) = 1 if t = 0.…”
Section: Introductionmentioning
confidence: 99%
“…[6] substitute the 0$\ell _{0}$‐norm x0$\Vert \mathbf {x}\Vert _{0}$ by a nonconvex sparsity‐promoting penalty function, that is Pa(x)badbreak=i=1npa(boldxi)goodbreak=i=1na|xi|a|xi|+1,$$\begin{equation} P_{a}(\mathbf {x})=\sum _{i=1}^{n}p_{a}(\mathbf {x}_{i})=\sum _{i=1}^{n}\frac{a|\mathbf {x}_{i}|}{a|\mathbf {x}_{i}|+1}, \end{equation}$$where pa(boldxi)badbreak=a|xi|a|xi|+1,0.33emagoodbreak>0$$\begin{equation*} p_{a}(\mathbf {x}_{i})=\frac{a|\mathbf {x}_{i}|}{a|\mathbf {x}_{i}|+1}, \ a>0 \end{equation*}$$is called the fraction function. In addition, the fraction function is also used to the matrix rank minimization problem [7, 8] and sparse non‐negative signal recovery [9]. It is easy to verify that pa(t)=0$p_{a}(t)=0$ if t=0$t=0$ and lima+pa(t)=1$\lim _{a\rightarrow +\infty }p_{a}(t)=1$...…”
Section: Introductionmentioning
confidence: 99%