1996
DOI: 10.1109/18.485730
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Some counterexamples in the theory of Weyl-Heisenberg frames

Abstract: We consider the causal channel g always generates a Weyl-Heisenberg frame gna+b, n,m E Z, when a , b > 0, ab < 1. Here g Z I Y ( t ) = exp (-nizy + 27riyt) g ( t -z), t E wWe truncate the channel response so that N , = 0 and AT, = 20.As before, the channel input is an i.i.d. sequence, and the noise is stationary and white with SNR,h,, =20 dB. We assume the number of feedforward taps is fixed at q = 10. Fig. 3 shows the optimal decision delay (defined as thlat which maximizes SNRDFE) versus the number of feedba… Show more

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Cited by 7 publications
(4 citation statements)
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“…One of the central motives of this article is hinted by the Daubechies conjecture [3, p. 981] which assumes that Gabor system is a frame for all αβ < 1 whenever g is a positive function with positive Fourier transform. This conjecture has been disproved by Janssen [8], yet in all known examples of functions which generates a Gabor system for all αβ < 1 we encounter some kind of positivity.…”
Section: Introduction and Main Resultsmentioning
confidence: 93%
“…One of the central motives of this article is hinted by the Daubechies conjecture [3, p. 981] which assumes that Gabor system is a frame for all αβ < 1 whenever g is a positive function with positive Fourier transform. This conjecture has been disproved by Janssen [8], yet in all known examples of functions which generates a Gabor system for all αβ < 1 we encounter some kind of positivity.…”
Section: Introduction and Main Resultsmentioning
confidence: 93%
“…One of the central motives of the article is hinted by the Daubechies conjecture [3, p. 981] which assumes that Gabor system is a frame for all αβ < 1 whenever g is positive function with positive Fourier transform. This conjecture has been disproved by Janssen [8], yet in all known examples of functions which generates a Gabor system for all αβ < 1 we encounter some kind of positivity.…”
Section: Introduction and Main Resultsmentioning
confidence: 93%
“…(i) γ(x) is piecewise continuous, (ii) card (supp γ(x)) ≤ (r + 1)M, where according to (18) supp γ(x) = {j : γ 0,j (x) ≡ 0} ⊆ {j :…”
Section: Gabor Frames With Totally Positive Functionsmentioning
confidence: 99%
“…The example of the Gaussian lead Daubechies to conjecture that F (g) = {(α, β) ∈ R 2 + : αβ < 1} whenever g is a positive function in L 1 with positive Fourier transform in L 1 [9, p. 981]. This conjecture was disproved in [18].…”
Section: Introductionmentioning
confidence: 99%