2009
DOI: 10.1515/crelle.2009.064
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Solving Fermat-type equations via modular ℚ-curves over polyquadratic fields

Abstract: We solve the diophantine equations x 4 + dy 2 = z p for d = 2 and d = 3 and any prime p > 349 and p > 131 respectively. The method consists in generalizing the ideas applied by Frey, Ribet and Wiles in the solution of Fermat's Last Theorem, and by Ellenberg in the solution of the equation x 4 + y 2 = z p , and we use Q-curves, modular forms and inner twists. In principle our method can be applied to solve this type of equations for other values of d. *

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Cited by 18 publications
(35 citation statements)
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“…In general, for forms of higher degree, the problem rapidly becomes more complicated -to illustrate its difficulty, it is worthwhile noting that the affirmative answer to this question, in case F (x, y) = xy(x + y) or x(x 2 − y 2 ), and z = 0, ±1, is equivalent to the asymptotic version of Wiles' theorem [58], née Fermat's Last Theorem, and to a special case of a result of Darmon and Merel [9], respectively. For irreducible forms (over Q[x, y]), the only results in the literature answering our question affirmatively are for certain diagonal quartic forms, such as F (x, y) = x 4 + y 4 (together with "covering" forms of higher degree), due to Ellenberg [16] and to Dieulefait and Jiménez Urroz [12]) (see also [2]). In particular, there are hitherto no primitive, irreducible cubic forms for which the above question has been addressed.…”
Section: Introductionmentioning
confidence: 72%
See 1 more Smart Citation
“…In general, for forms of higher degree, the problem rapidly becomes more complicated -to illustrate its difficulty, it is worthwhile noting that the affirmative answer to this question, in case F (x, y) = xy(x + y) or x(x 2 − y 2 ), and z = 0, ±1, is equivalent to the asymptotic version of Wiles' theorem [58], née Fermat's Last Theorem, and to a special case of a result of Darmon and Merel [9], respectively. For irreducible forms (over Q[x, y]), the only results in the literature answering our question affirmatively are for certain diagonal quartic forms, such as F (x, y) = x 4 + y 4 (together with "covering" forms of higher degree), due to Ellenberg [16] and to Dieulefait and Jiménez Urroz [12]) (see also [2]). In particular, there are hitherto no primitive, irreducible cubic forms for which the above question has been addressed.…”
Section: Introductionmentioning
confidence: 72%
“…The first is to solve the equations, as in Tzanakis and de Weger [53], through a combination of lower bounds in linear forms in complex and p-adic logarithms, with techniques from computational Diophantine approximation. A second method is to appeal to the syzygy (12), which shifts the problem to one of determining the S-integral points on a collection of (Mordell) elliptic curves. Since the number of such curves is exponential in the cardinality of S F , in many situations this method appears impractical.…”
Section: Examples and Computationsmentioning
confidence: 99%
“…The authors have subsequently learned that a similar technique for finding γ also appeared in [Dieulefait and Urroz 2009] (where K β is polyquadratic).…”
Section: Review Of ‫-ޑ‬Curves and Their Attached Galois Representationsmentioning
confidence: 99%
“…(iv) Dieulefait and Urroz [15] used the method of Galois representations attached to Q-curves to solve the Diophantine equation 3x 2 + y 4 = z n . The authors suggest that their method can be applied to solve this type of equations with 3 replaced by other values of a.…”
Section: Introductionmentioning
confidence: 99%