1994
DOI: 10.4064/aa-67-2-177-196
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Solving elliptic diophantine equations by estimating linear forms in elliptic logarithms

Abstract: 1. Introduction. In [Z], Zagier describes several methods for explicitly computing (large) integral points on models of elliptic curves defined over Q. Here we are interested in the computation of all integral points on a given Weierstraß equation for an elliptic curve E/Q, but not merely by reducing the original diophantine equation to an equivalent finite set of Thue equations which are subsequently solved by elementary, algebraic or analytic methods (see [TdW] and [STz]). On the contrary, we adopt a more n… Show more

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Cited by 124 publications
(127 citation statements)
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“…Thus bounds from elliptic transcendence theory are applicable. We use Théorème 2.1 in [3] but see also [24] where an explicit version of David's Theorem appears on page 20. The nature of the bound is log |x n | v log n log log n,…”
Section: Recall That a B And B A Are Equivalent To A = O(b)mentioning
confidence: 99%
“…Thus bounds from elliptic transcendence theory are applicable. We use Théorème 2.1 in [3] but see also [24] where an explicit version of David's Theorem appears on page 20. The nature of the bound is log |x n | v log n log log n,…”
Section: Recall That a B And B A Are Equivalent To A = O(b)mentioning
confidence: 99%
“…In case f (u, v) = 0 is a Weierstrass equation, a quartic equation of type v 2 = Q(u) for some quartic polynomial Q, or a general cubic elliptic equation, G(u, v) is constant with value 2; see [16], [21] and [20]. Now put…”
Section: The Elliptic Integralsmentioning
confidence: 99%
“…The group E(R), defined by y 2 = q(x), has the identity component E 0 (R), and in the real case-we remind the reader that in this case q(x) = 0 has three real roots e 1 > e 2 > e 3 -also the bounded component [16]). In the complex case-that is, when q(x) = 0 has a single real root-we have E 0 (R) = E(R), and φ is defined on the whole of E(R).…”
Section: Linear Forms In Elliptic Logarithmsmentioning
confidence: 99%
See 1 more Smart Citation
“…[37]) or on lower bounds for linear forms in elliptic logarithms (see e.g. [35]) to find all integer solutions (X, Y ) to Y 2 = X 3 − n 2 X and check to see which, if any, yield solutions to (1.3). To find positive integral solutions to (1.3), for all squarefree n up to some bound, say n ≤ N , it is computationally much more efficient however, to rely upon Theorem 2.2.…”
Section: Computationsmentioning
confidence: 99%