2015
DOI: 10.1016/j.cnsns.2014.10.006
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Solutions for the turbulent classical wake using Lie symmetry methods

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Cited by 9 publications
(8 citation statements)
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“…Various closure models—which in general may depend on x , y , ufalse¯, normal∂ufalse¯/normal∂y, and higher partial derivatives of ufalse¯—are discussed in §3. A detailed derivation of the governing equations is given in [32]. For completeness, an outline is provided below.…”
Section: Mathematical Model For a Two-dimensional Turbulent Classical Far Wakementioning
confidence: 99%
See 3 more Smart Citations
“…Various closure models—which in general may depend on x , y , ufalse¯, normal∂ufalse¯/normal∂y, and higher partial derivatives of ufalse¯—are discussed in §3. A detailed derivation of the governing equations is given in [32]. For completeness, an outline is provided below.…”
Section: Mathematical Model For a Two-dimensional Turbulent Classical Far Wakementioning
confidence: 99%
“…Let L be the length in the x -direction, beyond which the reduction in velocity is small enough to be neglected, and E C the characteristic effective kinematic viscosity. The turbulent or modified Reynolds number is then ReT=ULEC, and is related to the Reynolds number, Re = U L / ν , by ReT=ReνEC. A turbulent region downstream of the object can develop for large Re , but in order for a turbulent boundary layer to exist, terms of order 1/ Re T must be neglected [32]. This is similar to the condition for a laminar boundary layer to exist, which requires terms of order 1/ Re to be neglected [31].…”
Section: Mathematical Model For a Two-dimensional Turbulent Classical Far Wakementioning
confidence: 99%
See 2 more Smart Citations
“…Various closure models -which in general may depend on x, y, ū, ∂ ū/∂y, and higher partial derivatives of ū -are discussed in Section 3. A detailed derivation of the governing equations is given in [32]. For completeness, an outline is provided below.…”
Section: (A) Governing Equationsmentioning
confidence: 99%