1980
DOI: 10.1039/p29800000243
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Sodium borohydride as a reagent for nucleophilic aromatic substitution by hydrogen: the role of hydride Meisenheimer adducts as reaction intermediates

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Cited by 22 publications
(13 citation statements)
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“…Such Meisenheimer anions can be stabilized by strongly electron‐withdrawing substituents (e.g. NO 2 ), but generally eliminate a hydride to give an aromatic product . The dibenzyl calcium reagents (DMAT) 2 Ca⋅(THF) 2 and (4‐ t Bu‐benzyl) 2 Ca clearly underperformed (DMAT=2‐Me 2 N‐α‐Me 3 Si‐benzyl).…”
Section: Methodsmentioning
confidence: 99%
“…Such Meisenheimer anions can be stabilized by strongly electron‐withdrawing substituents (e.g. NO 2 ), but generally eliminate a hydride to give an aromatic product . The dibenzyl calcium reagents (DMAT) 2 Ca⋅(THF) 2 and (4‐ t Bu‐benzyl) 2 Ca clearly underperformed (DMAT=2‐Me 2 N‐α‐Me 3 Si‐benzyl).…”
Section: Methodsmentioning
confidence: 99%
“…All these data are in agreement with those reported in the literature. [45] Thus, according to NMR spectroscopic data we are adsorbing into the zeolite a solution of the sodium salt of pure Meisenheimer complex, and no other species, particularly 2,4-dinitroaniline, could be observed during adsorption.…”
Section: Resultsmentioning
confidence: 98%
“…Also the 13 C NMR spectrum agrees completely with the structure of the s complex formed by hydride attack at the 3-position of 2,4-dinitroaniline. [44][45][46] In addition to NMR spectroscopy, the Meisenheimer complex in acetonitrile solution exhibits a characteristic UV/Vis absorption band at 578 nm that can be used to identify unambiguously its presence in mixtures containing neutral 2,4-dinitroaniline (l max = 333 nm). All these data are in agreement with those reported in the literature.…”
Section: Resultsmentioning
confidence: 99%
“…Because the amount of this metabolite from culture was insufficient for thorough spectroscopic analysis, it was necessary to synthesize the complex. From the literature, it was known that hydride complexes of polynitroaromatic compounds can be generated by hydride transfer by using NaBH 4 , Bu 3 SnH, (H 3 C) 4 NBH 4 , or (H 3 C) 4 NB 3 H 8 as donor (2,4,7,9,18,21). However, none of these studies included a strong acid, such as picric acid (with a pK a of 0.38, according to reference 3).…”
Section: Discussionmentioning
confidence: 99%