2022
DOI: 10.1002/rsa.21135
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Smoothed counting of 0–1 points in polyhedra

Abstract: Given a system of linear equations ℓifalse(xfalse)=βi$$ {\ell}_i(x)={\beta}_i $$ in an n$$ n $$‐vector x$$ x $$ of 0–1 variables, we compute the expectation of exp{}prefix−∑iγi()ℓifalse(xfalse)prefix−βi2$$ \exp \left\{-{\sum}_i{\gamma}_i{\left({\ell}_i(x)-{\beta}_i\right)}^2\right\} $$, where x$$ x $$ is a vector of independent Bernoulli random variables and γi>0$$ {\gamma}_i>0 $$ are constants. The algorithm runs in quasi‐polynomial nOfalse(lnnfalse)$$ {n}^{O\left(\ln n\right)} $$ time under some sparseness c… Show more

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Cited by 1 publication
(2 citation statements)
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“…If H is not regular, one can choose instead the maximum entropy distribution, which also ensures that the expected number of selected edges containing any given vertex is exactly 1, while the weights of all perfect matchings remain equal. The maximum entropy distribution exists if an only if there exists a positive fractional perfect matching, that is, an assignment of positive real weights to the edges of H such that for every vertex of H the sum of weights of the edges containing it is exactly 1, see [Ba23] for details.…”
Section: Introduction and The Main Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…If H is not regular, one can choose instead the maximum entropy distribution, which also ensures that the expected number of selected edges containing any given vertex is exactly 1, while the weights of all perfect matchings remain equal. The maximum entropy distribution exists if an only if there exists a positive fractional perfect matching, that is, an assignment of positive real weights to the edges of H such that for every vertex of H the sum of weights of the edges containing it is exactly 1, see [Ba23] for details.…”
Section: Introduction and The Main Resultsmentioning
confidence: 99%
“…Proof. The inequality of Part (1) is proved, for example, in [Ba23], see Lemma 6.1 there. To prove the inequality of Part (2), let f (α) = sin(τ α) and g(α) = τ sin α.…”
Section: Proof Of Theorem 11mentioning
confidence: 99%