Based on experimental evidence from the 144 Sm(α,2n) reaction, the 3484.7-keV 6 + state in 146 Gd is identified as the highest-spin member of the 3 − ⊗ 3 − two-phonon octupole quartet. In the harmonic approximation for noninteracting phonons, a degenerate two-phonon multiplet should occur at twice the energy of the one-phonon state. For low-energy quadrupole (λ = 2) shape vibrations, multiphonon states have been characterized in many even-even nuclei; however, these structures frequently exhibit large anharmonicities, even in nearly spherical nuclei [1]. The octupole (λ = 3) mode in doubly magic nuclei likely comes much closer to the ideal harmonic oscillator as a result of the smaller vibrational amplitudes and the larger number of particles participating in the motion. Indeed, a two-phonon 3 − ⊗ 3 − quartet (J π = 0 + , 2 + , 4 + , and 6 + ) should occur at twice the energy of the octupole phonon and is expected to decay with B(E3) values which are twice that of the 3 − → 0 + transition [1,2]. Unfortunately, two-phonon excitations of the octupole type have proven difficult to identify.It is not surprising that 208 Pb, with its 3 − first-excited state at 2614 keV and B(E3; 3 − → 0 + ) of 34 W.u.[3], has been the subject of many searches for the two-phonon octupole quartet at about 5.2 MeV, that is, at 2hω 3 [4]. Firm evidence, an observed cascade of two E3 transitions from a 0 + state at 5241 keV, for the lowest-spin member of the two-phonon quartet in 208 Pb has been obtained [5]. In addition, candidates for the 2 + and 4 + members of the quartet at nearly harmonic energies have been proposed, but these identifications are based primarily on energy arguments and E1 transition rates; the signature cascade of E3 transitions was not observed [6]. Transfer reaction and inelastic light-ion scattering studies [7] support these assignments, but no clear candidate for the 6