2009
DOI: 10.1007/s00211-009-0248-0
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Shape preserving properties of generalized Bernstein operators on Extended Chebyshev spaces

Abstract: Abstract. We study the existence and shape preserving properties of a generalized Bernstein operator B n fixing a strictly positive function f 0 , and a second function f 1 such that f 1 /f 0 is strictly increasing, within the framework of extended Chebyshev spaces U n . The first main result gives an inductive criterion for existence: suppose there exists a Bernstein operator B n : C[a, b] → U n with strictly increasing nodes, fixing f 0 , f 1 ∈ U n . If U n ⊂ U n+1 and U n+1 has a non-negative Bernstein basi… Show more

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Cited by 53 publications
(39 citation statements)
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“…we get a discrete Markov type operator which preserves the above mentioned test function (see [2]). In this article we obtain a class of Markov type operators of the form (2) (some functionals k n;k ðf Þ are of integral form, but not all) which preserves the monomial e j ; j P 1.…”
Section: Introductionmentioning
confidence: 94%
“…we get a discrete Markov type operator which preserves the above mentioned test function (see [2]). In this article we obtain a class of Markov type operators of the form (2) (some functionals k n;k ðf Þ are of integral form, but not all) which preserves the monomial e j ; j P 1.…”
Section: Introductionmentioning
confidence: 94%
“…If these equalities can be satisfied, they uniquely determine the location of the nodes and the values of the coefficients, cf. [4,Lemma 5]; in other words, there is at most one Bernstein operator B n of the form (2) satisfying (3). We will consistently use the following notation.…”
Section: Definitions and Backgroundmentioning
confidence: 99%
“…Theorem 5.1) that given any polynomial f 1 (x), strictly increasing on [a, b], and of degree m, it is always possible to find a generalized Bernstein operator fixing 1 and f 1 , on the space P n [a, b] with the standard Bernstein basis, provided that n ≥ m and that n is "sufficiently large". The special case f 1 (x) = x j , [a, b] = [0, 1], had been previously solved in [4,Proposition 11]; on the other hand, it is known that such operators do not exist if we are required to fix f 0 (x) = x i and f 1 (x) = x j on [0, 1], 1 ≤ i < j, cf. [11,Theorem Within the line of research followed here, previous work has focused on spaces different or more general than spaces of polynomials (cf.…”
Section: Introductionmentioning
confidence: 99%
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