2002
DOI: 10.1155/s016117120201270x
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Separable functors in corings

Abstract: We develop some basic functorial techniques for the study of the categories of comodules over corings. In particular, we prove that the induction functor stemming from every morphism of corings has a left adjoint, called ad-induction functor. This construction generalizes the known adjunctions for the categories of Doi-Hopf modules and entwined modules. The separability of the induction and ad-induction functors are characterized, extending earlier results for coalgebra and ring homomorphisms, as well as for e… Show more

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Cited by 30 publications
(47 citation statements)
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“…Following [10], a coring homomorphism from the A-coring C to the B-coring D is a pair (ϕ, ρ), where ρ : A → B is a homomorphism of k-algebras and ϕ : C → D is a homomorphism of A-bimodules such that C and f ′ , g ′ ∈ C * given by the formulas…”
Section: Quasi-frobenius Coring Homomorphismsmentioning
confidence: 99%
“…Following [10], a coring homomorphism from the A-coring C to the B-coring D is a pair (ϕ, ρ), where ρ : A → B is a homomorphism of k-algebras and ϕ : C → D is a homomorphism of A-bimodules such that C and f ′ , g ′ ∈ C * given by the formulas…”
Section: Quasi-frobenius Coring Homomorphismsmentioning
confidence: 99%
“…This in fact comes from a general setting. Namely, if we have any (A ′ , A)-corings morphism (φ, ϕ) : (C ′ : A ′ ) → (C : A) in the sense of [10]. That is ϕ : A ′ → A is a rings morphism and φ : C ′ → C is by scalar restriction an A ′ -bilinear map satisfying…”
Section: It Is Clear That D Is An A-bilinear and That (Dmentioning
confidence: 99%
“…In that case (−) φ admits − C D as right adjoint, see [10] or [6] for more details. Proposition 3.5 gives a right adjoint functor to (−) ξ without requiring any assumption on the cowreath product C ⊗ A M .…”
Section: Is Clear That G Is Left A-linear Let Us Check Thatmentioning
confidence: 99%
“…Now, being Σ † = Σ ′ ⊗ R R firm as a right R-module, it has a structure of left Σ † ⊗ R Σ-comodule with coaction (see (21)) Proof. First, observe that f is nothing but the inverse of the isomorphism Σ ′ ⊗ R d Σ .…”
Section: But This Equality Follows By Applying the Isomorphism σmentioning
confidence: 99%