2018
DOI: 10.1002/mana.201700144
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Semi‐linear wave models with power non‐linearity and scale‐invariant time‐dependent mass and dissipation, II

Abstract: This paper is a continuation of our recent paper . We will consider the semi‐linear Cauchy problem for wave models with scale‐invariant time‐dependent mass and dissipation and power non‐linearity. The goal is to study the interplay between the coefficients of the mass and the dissipation term to prove global existence (in time) of small data energy solutions assuming suitable regularity on the L2 scale with additional L1 regularity for the data. In order to deal with this L2 regularity in the non‐linear part, … Show more

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Cited by 65 publications
(64 citation statements)
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“…and, hence, as j → ∞ in (39) we see that the lower bound for U (z) is not finite. Therefore, in order to guarantee the existence of U (z), it must hold the converse inequality for z.…”
Section: Iteration Argument: Critical Casementioning
confidence: 84%
“…and, hence, as j → ∞ in (39) we see that the lower bound for U (z) is not finite. Therefore, in order to guarantee the existence of U (z), it must hold the converse inequality for z.…”
Section: Iteration Argument: Critical Casementioning
confidence: 84%
“…For further considerations on how the quantity describes the interplay between the damping term 1+t u t and the mass term 2 (1+t) 2 u one can see. 14 Recently, (1.3) has been studied in D'Abbicco and Palmieri, Nunes do Nascimento et al, Palmieri, and Palmieri and Reissig [15][16][17][18][19][20] under different assumptions on .…”
Section: Introductionmentioning
confidence: 99%
“…( As in the paper, 25 we also prove the optimality of the condition (C1) for p k . One choice for the parameters q 1 , q 2 and r 1 , … , r 6 is the following: q 1 = 3(p k − 1), q 2 = 6, r 1 = 6, r 2 = 3, r 3 = 3(p k − 1), r 4 = 6(p k − 1) 3(p k − 1) − 2 , r 5 = 3(p k − 1), r 6 = 6.…”
Section: Casementioning
confidence: 74%
“…and data belonging to  0 m,1 with m ∈ [ 1, 6∕5), where exactly one exponent is not above the exponent p c (m, ). Without loss of generality we choose 1 < p k 1 < p c (m, ) and p k 2 , p k 3 > p c (m, ), where the exponent p c (m, ) is defined by (25). Let us choose the evolution space (35) with the norm (39).…”
Section: Philosophy Of Our Approachmentioning
confidence: 99%