2008
DOI: 10.1090/s0002-9939-08-09032-1
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Semi-compactness of positive Dunford–Pettis operators on Banach lattices

Abstract: Abstract. We investigate Banach lattices on which each positive DunfordPettis operator is semi-compact and the converse. As an interesting consequence, we obtain Theorem 2.7 of Aliprantis-Burkinshaw and an element of Theorem 1 of Wickstead.

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Cited by 8 publications
(11 citation statements)
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“…Also, this result generalizes the implication (3) =⇒ (1) of Theorem 2.2 of [2]. In fact, we have Theorem 2.5.…”
Section: Example It Follows From Proposition 24 That the Closed Unisupporting
confidence: 80%
“…Also, this result generalizes the implication (3) =⇒ (1) of Theorem 2.2 of [2]. In fact, we have Theorem 2.5.…”
Section: Example It Follows From Proposition 24 That the Closed Unisupporting
confidence: 80%
“…As we asked in [6], a semi-compact operator is not necessary Dunford-Pettis, and conversely a Dunford-Pettis operator is not necessary semi-compact. For example, the identity operator Id l 1 : l 1 → l 1 is Dunford-Pettis but it is not semi-compact and conversely, the identity operator Id c : c → c is semi-compact but it is not Dunford-Pettis where c is the Banach lattice of all convergent sequences.…”
Section: Corollary 23 Let E and F Be Two Banach Lattices If The Nomentioning
confidence: 92%
“…And in the paper [4], Banach lattices on which each positive Dunford-Pettis operator is semi-compact, were investigated. Conversely, a semi-compact operator is not necessary Dunford-Pettis.…”
Section: The Dunford-pettis Property Of Semi-compact Operatorsmentioning
confidence: 99%
“…For the converse of results of [4], we will show that if E and F are two Banach lattices such that F is Dedekind σ-complete (resp. the norm of E is order continuous) and F is discrete or E has the Dunford-Pettis property, then each semi-compact operator T : E → F is Dunford-Pettis if and only if E has the Schur property or the norm of F is order continuous.…”
Section: Introduction and Notationmentioning
confidence: 96%
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