2017
DOI: 10.1515/bpasts-2017-0004
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Scheduling of unit-length jobs with bipartite incompatibility graphs on four uniform machines

Abstract: Abstract. In the paper we consider the problem of scheduling n identical jobs on 4 uniform machines with speeds s 1 ¸ s 2 ¸ s 3 ¸ s 4 , respectively. Our aim is to find a schedule with a minimum possible length. We assume that jobs are subject to some kind of mutual exclusion constraints modeled by a bipartite incompatibility graph of degree ∆, where two incompatible jobs cannot be processed on the same machine. We show that the general problem is NP-hard even if s 1 = s 2 = s 3 . If, however, ∆ • 4 and s 1 ¸ … Show more

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Cited by 13 publications
(13 citation statements)
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“…Hence, we establish the complexity status of scheduling on uniform machines. This result justifies the research on families of graphs more restrictive than just being bipartite, like bipartite with bounded degree considered in [7], [8], and [23]. Moreover, due to our best…”
Section: Introductionsupporting
confidence: 76%
“…Hence, we establish the complexity status of scheduling on uniform machines. This result justifies the research on families of graphs more restrictive than just being bipartite, like bipartite with bounded degree considered in [7], [8], and [23]. Moreover, due to our best…”
Section: Introductionsupporting
confidence: 76%
“…As demonstrated in [84,85], colorings of edges in the graph may be used to model a certain job-shop scheduling system consisting of unit-time jobs assigned to specific pairs of machines. In the case of the mixed graph G = (V, A, E), it is convenient to look upon arc (v i , v j ) ∈ A as a unit-time data transmission from machine v i to machine v j requiring the cooperation of machines v i and v j , which cannot simultaneously process other jobs.…”
Section: Colorings Of Arcs and Edges Of The Mixed Graphmentioning
confidence: 99%
“…The authors of (Furmańczyk and Kubale, 2017a) also considered bisubquartic graphs and m = 4 machines. They proved that, if s 1 12s 2 and s 2 = s 3 = s 4 , then problem Q4|U ET, bisubquartic|C max can be solved to optimality in time O(n 1.5 ).…”
Section: Standard Uniform Machinesmentioning
confidence: 99%
“…Therefore, we have the following: Theorem 3. (Furmańczyk and Kubale, 2017a) If s 1 12s 2 and s 2 = s 3 = s 4 then the problems Q4|U ET, bisubquartic|C max and Q4|U ET, bisubquartic| C i can be solved in O(n 1.5 ) time.…”
Section: Standard Uniform Machinesmentioning
confidence: 99%