2014
DOI: 10.1016/j.dam.2012.05.027
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Scheduling arc maintenance jobs in a network to maximize total flow over time

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Cited by 29 publications
(48 citation statements)
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“…In particular, the absence of c 3 |E|-approximation algorithms for some c > 0 for general graphs indicates that heuristics and IP-based methods [2,3,4] are a good way of approaching this problem. An interesting open question is whether the inapproximability results carry over to series-parallel graphs, as the network motivating [2,3,4] is series-parallel. Our results on the power of preemption as well as the efficient algorithm for preemptive instances show that allowing preemption is very desirable.…”
Section: Resultsmentioning
confidence: 99%
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“…In particular, the absence of c 3 |E|-approximation algorithms for some c > 0 for general graphs indicates that heuristics and IP-based methods [2,3,4] are a good way of approaching this problem. An interesting open question is whether the inapproximability results carry over to series-parallel graphs, as the network motivating [2,3,4] is series-parallel. Our results on the power of preemption as well as the efficient algorithm for preemptive instances show that allowing preemption is very desirable.…”
Section: Resultsmentioning
confidence: 99%
“…While network problems and scheduling problems individually are fairly well understood, the combination of both areas that results from scheduling network maintenance has only recently received some attention [2,4,17,1,11] and is theoretically hardly understood.…”
Section: Introductionmentioning
confidence: 99%
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“…The problem in general is NP‐hard . In this proof, the reduction gave rise to a network with a single transhipment node, which was not balanced, and in which the set of arcs with associated jobs did not contain a minimum cut.…”
Section: Network With Single Transhipment Nodementioning
confidence: 97%
“…Proposition If the network is series‐parallel and balanced, then it is optimal to schedule all jobs at the same time . Proof For a network N=(V,A,s,t,u) and a subset JA let FN,J denote the maximum flow value in the network N=(V,AJ,s,t,u|AJ). The statement that it is optimal to schedule all jobs at the same time is equivalent to FN,JJ+FN,FN,J+FN,J for all J,JA (see ). We prove the proposition by induction on the structure of the graph.…”
Section: General Networkmentioning
confidence: 99%