“…choose h that satisfies (11) and set θ k = θ k = 1 and i = 0 2. solve (17) for θ * and estimate Ψ(θ * l ) for each θ * l , l ∈ {1, · · · , m} 3. if for any ϑ l ∈ Ψ(θ * l ), (11) is violated with θ k l = ϑ l 4. if for all ς l ∈ Ψ(θ * l ), θ * l satisfies (11) with θ k l = ς l and θ k l = θ * l 5. update θ k l using θ * l at the next transmission time and GOTO step 12 6. else if any K * satisfies (11) 7. update K using K * at the next transmission time and GOTO step 12 8. else 9. replace l-th actuator with a new actuator that satisfies (11), set θ k l = θ k l = 1 at the next transmission time and GOTO step 12 10. end if 11. else 12. i = i + 1 and GOTO step 2 13. end if Remark 5: As mentioned earlier in Remark 4, when a perfect model is implemented for control and fault identification (i.e., ∆G = 0), the estimation confidence interval for θ k l , Ψ(θ * l ), shrinks to a point, θ * l . In this case, the fault accommodation logic can be modified as shown in the following algorithm.…”