2020
DOI: 10.1007/jhep03(2020)171
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Revisiting the classifications of 6d SCFTs and LSTs

Abstract: Gauge-theoretic anomaly cancellation predicts the existence of many 6d SCFTs and little string theories (LSTs) that have not been given a string theory construction so far. In this paper, we provide an explicit construction of all such "missing" 6d SCFTs and LSTs by using the frozen phase of F-theory. We conjecture that the full set of 6d SCFTs and LSTs is obtained by combining the set of theories constructed in this paper with the set of theories that have been constructed in earlier literature using the unfr… Show more

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Cited by 46 publications
(80 citation statements)
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“…For su(2) gauge theory paired with a tensor of charge −2, anomaly cancelation considerations imply we have eight half-hypermultiplets in the fundamental representation. Though this might suggest the matter fields transform in the vector representation of Spin(8), the F-theory realization of this model admits only a Spin (7) flavor symmetry at the superconformal fixed point [5], which is in fact confirmed by field theory considerations as well [35,48]. So in this case, the matter fields transform as halfhypermultiplets in the (2, 8) of su(2) × so (7).…”
Section: Candidate U (1)'smentioning
confidence: 65%
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“…For su(2) gauge theory paired with a tensor of charge −2, anomaly cancelation considerations imply we have eight half-hypermultiplets in the fundamental representation. Though this might suggest the matter fields transform in the vector representation of Spin(8), the F-theory realization of this model admits only a Spin (7) flavor symmetry at the superconformal fixed point [5], which is in fact confirmed by field theory considerations as well [35,48]. So in this case, the matter fields transform as halfhypermultiplets in the (2, 8) of su(2) × so (7).…”
Section: Candidate U (1)'smentioning
confidence: 65%
“…There is a U (1) R coming from the six fundamentals of su(4), which transform under U (6) ∼ SU (6) × U (1) R . However, this is the only U (1) that shows up: the flavor symmetry SO (7) of the leftmost −2 tensor is gauged by su(4) so (6), but U (1) × SU (4) is not a subgroup of SO (7). As a result, there is no U (1) factor under which bifundamental of su(2) × su(4) transforms.…”
Section: Examples With Su(2) Gauge Symmetrymentioning
confidence: 99%
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