2013
DOI: 10.1007/978-3-642-39310-5_25
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Reversal on Regular Languages and Descriptional Complexity

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Cited by 12 publications
(8 citation statements)
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“…This improves the result from [8], where an alphabet of size growing exponentially with n is used to produce the whole range of complexities for the concatenation operation. Our result complements similar results from [10,14], where a linear alphabet is used to get the whole range of complexities for the reversal and Kleene closure operations.…”
Section: Discussionsupporting
confidence: 82%
See 1 more Smart Citation
“…This improves the result from [8], where an alphabet of size growing exponentially with n is used to produce the whole range of complexities for the concatenation operation. Our result complements similar results from [10,14], where a linear alphabet is used to get the whole range of complexities for the reversal and Kleene closure operations.…”
Section: Discussionsupporting
confidence: 82%
“…The result for reversal and star was improved in [10,14] by showing that a linear alphabet is enough to produce the whole range of complexities.…”
Section: Introductionmentioning
confidence: 99%
“…If n ≥ 5, then consider the language L = cKc, where K is a regular language over the alphabet {a, b} with κ(K) = n − 3 meeting the upper bound 2 n−3 for reversal [24]. The quotient automaton of L without the empty state is shown in Figure 11.…”
Section: Reversalmentioning
confidence: 99%
“…Now we show that a binary alphabet, say Σ = {a, b}, is not enough to reach the upper bound. Let a ∈ Σ be a letter such that 0δ It is known that in the case of the class of all regular languages the resulted language of the reversal operation can have any state complexity in range of integers [log 2 n, 2 n ] [17,23], thus there are no gaps (magic numbers) in the interval of possible state complexities. The next theorem states that the situation is similar for the case of bifix-free languages.…”
Section: 2mentioning
confidence: 99%