“…Hence, G=K G P has only one non-linear irreducible character, say w, PnP 0 ¼ uðwÞ and uðwÞ consists of three conjugacy classes of P. Now we regard w as an irreducible character of G. Then, since K c kerðwÞ, KðPnP 0 Þ ¼ uðwÞ consists of three conjugacy classes of G and each element in KðPnP 0 Þ is a 2-element. This implies that every element in PnP 0 acts fixed-point freely on K. Therefore, since P is a 2-group of class 2, we conclude by [13,Lemma 19.1] that P G Q 8 and G is a Frobenius group with kernel K and complement Q 8 . Observe that there exists w A Irr 1 ðGÞ such that uðwÞ consists of four conjugacy classes of G, a contradiction.…”