Abstract:To a sorceress in an enchanted theatre c p m c This says ∂x (x n c p mSimilarly one gets a similar equation of the form ∂p (. Since e.g. (∂/∂x)x n = nx n−1 it seems awkward however to write out ∂x in terms of ∂/∂x. One (awkward) solution would be to define an operatorThis seems rather bizarre, but appears to be consistent, and could be written (A30) ∂x = Q(∂/∂x) and ∂p = T x q Q(∂/∂p). We emphasize that Q goes with the derivation and acts only on constants produced via differentiation (i.e. Q((∂/∂x)ax
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