1991
DOI: 10.1016/0019-3577(91)90014-x
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Regular operators from and into a small Riesz space

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Cited by 16 publications
(34 citation statements)
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“…. , m} and y ∈ L + with h(y) = f j (y) (1),...,(α) we have f j (y) (α+1) = 0. Clearly we also have for all j ∈ {1, .…”
Section: (α)mentioning
confidence: 99%
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“…. , m} and y ∈ L + with h(y) = f j (y) (1),...,(α) we have f j (y) (α+1) = 0. Clearly we also have for all j ∈ {1, .…”
Section: (α)mentioning
confidence: 99%
“…, 0) ∈ Z the bound (3.26) yields that m i=1 h (α+1) x * i > 0. These considerations allow us to define (1),..., (α) . To see this, fix i ∈ {1, .…”
Section: Which Contradicts (324) By the Symmetry Of The Situation Wmentioning
confidence: 99%
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“…In [2] the space l ∞ 0 of all real sequences which are constant except for a finite number of terms is investigated. This vector lattice is not Dedekind complete.…”
Section: A Space Of Operatorsmentioning
confidence: 99%