2020
DOI: 10.1021/acsomega.0c04170
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Reduced Reaction Mechanisms for Ethanol under Ultra-lean Conditions in Internal Combustion Engines

Abstract: Chemical kinetics models for ethanol under ultra-lean engine conditions were evaluated to couple with CFD multidimensional simulations of a spark-assisted homogeneous charge compression ignition (HCCI) rotary engine. Five reduced reaction sets proper for CFD simulations and two detailed reaction mechanisms for comparison were tested by simulating ignition delay times, laminar flame speeds, and a single-cycle HCCI engine with virtual piston dimensions. The simulated results of the new mechanism with 188 reactio… Show more

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Cited by 4 publications
(3 citation statements)
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“…The increasing energy share of hydrogen decreased the ethene emissions compared with E100 at all engine speeds, because of the higher in‐cylinder temperature with hydrogen leading to oxidation of pyrolytic products (ethene), thus indicating lower ethene formation 9 . The oxidation of ethene can be explained by Eqn (26): 10 C2H41emgoodbreak+1emnormalO1em1emCH2HCO1emgoodbreak+1emnormalHwhere O is the free oxygen radical, CH 2 HCO is the acetyl radical and H is the free hydrogen radical.…”
Section: Resultsmentioning
confidence: 99%
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“…The increasing energy share of hydrogen decreased the ethene emissions compared with E100 at all engine speeds, because of the higher in‐cylinder temperature with hydrogen leading to oxidation of pyrolytic products (ethene), thus indicating lower ethene formation 9 . The oxidation of ethene can be explained by Eqn (26): 10 C2H41emgoodbreak+1emnormalO1em1emCH2HCO1emgoodbreak+1emnormalHwhere O is the free oxygen radical, CH 2 HCO is the acetyl radical and H is the free hydrogen radical.…”
Section: Resultsmentioning
confidence: 99%
“…Ethene is one of the intermediate products which are formed during ethanol oxidation 8 . Ethene forms as a product of thermal pyrolysis from ethanol as given in Eqn (1) 9,10 C2H5OH1em)(goodbreak+normalM1em1emC2H41emgoodbreak+0.75emH2normalO1em)(goodbreak+normalMwhere M is the third body and H 2 O is water vapor.…”
Section: Introductionmentioning
confidence: 99%
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