“…We can represent a mesh design procedure as a sequence of the next steps, those are provided in iterations for every block 1. Using the grid obtained in a previous iteration to solve the equation 912(1,1) = cos jl yu(i, l)922(i, 1), i, / = 0,1; gii(,)(x + y) = 922(, )(x + y), , = (6) for the parameters a, b, c, a, , 8. Let (7) Then = a + 2a01 + 7012, = 6a + 26a1 + 7l2, 9?2 = b0 -a0i -/3/ -70i1, = b-&i-6/3l-S7il, 92 = co+2floi+70i2, 62 = 5c+ 28i+à7i2.…”