2021
DOI: 10.1112/topo.12205
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Random walks and quasi‐convexity in acylindrically hyperbolic groups

Abstract: Arzhantseva proved that every infinite-index quasi-convex subgroup H of a torsion-free hyperbolic group G is a free factor in a larger quasi-convex subgroup of G. We give a probabilistic generalization of this result. That is, we show that when R is a subgroup generated by independent random walks in G, then H, R ∼ = H * R with probability going to one as the lengths of the random walks go to infinity and this subgroup is quasi-convex in G. Moreover, our results hold for a large class of groups acting on hyper… Show more

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Cited by 2 publications
(2 citation statements)
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References 60 publications
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“…This is a result of Maher-Tiozzo [MT18] who proved that a (non-elementary) random walk on a group acting on a hyperbolic space X makes linear progress in X. This result feeds into the proof of several others, for example on the translation length [MT18], random subgroups [MS19,AH21], various kinds of projections [ST19], and deviation from quasi-geodesics [MS20], as well as the already mentioned central limit theorem for acylindrically hyperbolic groups, and results on counting measures, see e.g. [GTT18].…”
Section: Introductionmentioning
confidence: 81%
“…This is a result of Maher-Tiozzo [MT18] who proved that a (non-elementary) random walk on a group acting on a hyperbolic space X makes linear progress in X. This result feeds into the proof of several others, for example on the translation length [MT18], random subgroups [MS19,AH21], various kinds of projections [ST19], and deviation from quasi-geodesics [MS20], as well as the already mentioned central limit theorem for acylindrically hyperbolic groups, and results on counting measures, see e.g. [GTT18].…”
Section: Introductionmentioning
confidence: 81%
“…The next lemma, which is used in the proof of Proposition 3.1, follows from arguments in [4]. We note that [1, Proposition 4.1] is related to the lemma, though neither implies the other. Lemma Let frakturg2$\mathfrak {g}\geqslant 2$ and let H$H$ be a convex‐compact subgroup of MCGfalse(Σgfalse)$MCG(\Sigma _{\mathfrak {g}})$.…”
Section: Preliminariesmentioning
confidence: 96%