2010
DOI: 10.1142/s1793042110003241
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Ramanujan's Cubic Continued Fraction and Ramanujan Type Congruences for a Certain Partition Function

Abstract: In this paper, we study the divisibility of the function a(n) defined by [Formula: see text]. In particular, we prove certain "Ramanujan type congruences" for a(n) modulo powers of 3.

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Cited by 62 publications
(38 citation statements)
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“…Recently, the following was discovered. Denote the Ramanujan cubic continued fraction by := [12]; see also its implications in [13,14]). Second, we remark that the strategy used in this paper can also be applied to the Ramanujan-Göllnitz-Gordon continued fraction (see p. 229 of Ramanujan's second notebook [25]; see also [1,20,21]; and also the paper by Chan and Huang [17], in which the authors provided a comprehensive theory of the Ramanujan-Göllnitz-Gordon continued fraction) and proved certain -identities.…”
Section: Discussionmentioning
confidence: 99%
“…Recently, the following was discovered. Denote the Ramanujan cubic continued fraction by := [12]; see also its implications in [13,14]). Second, we remark that the strategy used in this paper can also be applied to the Ramanujan-Göllnitz-Gordon continued fraction (see p. 229 of Ramanujan's second notebook [25]; see also [1,20,21]; and also the paper by Chan and Huang [17], in which the authors provided a comprehensive theory of the Ramanujan-Göllnitz-Gordon continued fraction) and proved certain -identities.…”
Section: Discussionmentioning
confidence: 99%
“…Now, we combine the two ways of writing K ∞ (a) to prove our lemma. Indeed, (15) and (18) = 1 3(q; q) ∞ J (1) + J (β) + J β 2 by (19).…”
Section: Set Up and A New Proof Of (2) And (3)mentioning
confidence: 98%
“…A consequence of Theorem 2 is Theorem 3 (Chan, Theorem 1 in [19]) For k ≥ 1 and n being nonnegative,…”
Section: Introductionmentioning
confidence: 99%
“…C. Chan in his papers [3,4,5] studied the congruence properties of the cubic partition function a(n), which is defined by ∞ n=0 a(n)q n = 1 (q; q) ∞ (q 2 ; q 2 ) ∞ = 1 f 1 f 2 .…”
Section: Introductionmentioning
confidence: 99%