2015
DOI: 10.1093/imrn/rnv044
|View full text |Cite
|
Sign up to set email alerts
|

R-Equivalence and A1-Connectedness in Anisotropic Groups

Abstract: We show that if G is an anisotropic, semisimple, absolutely almost simple, simply connected group over a field k, then two elements of G over any field extension of k are R-equivalent if and only if they are A 1equivalent. As a consequence, we see that Sing * (G) cannot be A 1 -local for such groups. This implies that the A 1 -connected components of a semisimple, absolutely almost simple, simply connected group over a field k form a sheaf of abelian groups.

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
2

Citation Types

0
38
0

Year Published

2015
2015
2023
2023

Publication Types

Select...
4
1

Relationship

0
5

Authors

Journals

citations
Cited by 12 publications
(38 citation statements)
references
References 10 publications
(11 reference statements)
0
38
0
Order By: Relevance
“…Therefore, there exists a pair of distinct R-equivalent elements in G(k). Since G is anisotropic, we have G(k) ≃ S(G)(k), by [4,Lemma 3.7]. Thus, the map S(G)(k) → π A 1 0 (G)(k) is not a bijection.…”
Section: Algebraic Groups and Their A 1 -Connected Componentsmentioning
confidence: 97%
See 4 more Smart Citations
“…Therefore, there exists a pair of distinct R-equivalent elements in G(k). Since G is anisotropic, we have G(k) ≃ S(G)(k), by [4,Lemma 3.7]. Thus, the map S(G)(k) → π A 1 0 (G)(k) is not a bijection.…”
Section: Algebraic Groups and Their A 1 -Connected Componentsmentioning
confidence: 97%
“…First assume that G is a semisimple, simply connected and absolutely almost simple group over k. If G is isotropic, then by [2, Theorem 4.3.1], Sing A 1 * G is A 1 -local and it follows that π A 1 0 (G)(F ) ≃ G(F )/R, for every field extension F/k (see [4,Theorem 3.4]). If G is anisotropic, this is [4, Theorem 4.2] (although it is stated there with the assumption that the base field is of characteristic 0, it is easy to see that the proof works over any infinite perfect field).…”
Section: Algebraic Groups and Their A 1 -Connected Componentsmentioning
confidence: 99%
See 3 more Smart Citations