Group theory arguments have been invoked to argue that odd parity order parameters cannot have line nodes in the presence of spin-orbit coupling. In this paper we show that these arguments do not hold for certain non-symmorphic superconductors. Specifically, we demonstrate that when the underlying crystal has a twofold screw axis, half of the odd parity representations vanish on the Brillouin zone face perpendicular to this axis. Many unconventional superconductors have nonsymmorphic space groups, and we discuss implications for several materials, including UPt3, UBe13, Li2Pt3B and Na4Ir3O8. 71.27.+a Unconventional superconducting materials include heavy fermion metals [1], organics [2], and cuprates [3]. The unconventionality of these materials is reflected in the symmetry of the Cooper pair wavefunction: in contrast to their 'conventional' counterparts, unconventional Cooper pairing not only breaks gauge but also crystal symmetry. This opens the possibility of odd parity pairing where by fermion antisymmetry, the spins are in a triplet state.Among unconventional superconductors, an important class are those whose order parameter vanishes somewhere on the Fermi surface. The presence or absence of these nodes determines the low energy excitations, and thus the low temperature thermodynamic and transport properties. It is generally stated that in the presence of spin-orbit interactions, an odd parity order parameter cannot have a line of nodes on the Fermi surface. This is known as Blount's theorem [4]. In contrast, this restriction does not exist for an even parity order parameter. There are, though, several heavy fermion superconductors where Knight shift data indicate that the Cooper pair spins are in a triplet state, yet thermodynamic measurements imply the existence of a line of nodes [5].The aim of the present paper is to investigate the generality of Blount's arguments. Specifically, we show that in crystals with a twofold screw axis, line nodes are possible whenever the Fermi surface intersects the Brillouin zone face perpendicular to this axis, even in the presence of spin-orbit interactions. Since many unconventional superconductors have non-symmorphic space groups, it provides a large class of counterexamples to Blount's theorem. We discuss implications for several materials of interest.In the presence of spin-orbit coupling, spin is no longer a good quantum number. On the other hand, Anderson has shown that because of fermion antisymmetry, one can write down analogues of Cooper pair singlets and triplets [6]. By Kramers theorem, one has two degenerate states present at k. Coupling them to the two degenerate states at -k, one has an even parity state that is a 'pseudo-spin' singlet, and an odd parity state that is a 'pseudo-spin' triplet. Blount has shown, though, that this puts restrictions on the form of the odd parity state [4]. A node requires the simultaneous fulfilling of two real equations. Since two equations in three variables are commonly satisfied on curves, and these intersect the Fermi...