1941
DOI: 10.1049/ji-2.1941.0043
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Proximity effect in solid and hollow round conductors

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Cited by 15 publications
(7 citation statements)
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“…In cases such as twin lines with opposing currents, the error in resistance will be the same as δP%, because power losses are proportional to resistance. The calculations were performed for 4 sets of (R/δ, d/R) ratios: (1, 2), (1,4), (4, 2), (4,4). In all the cases, typical variants of currents in the bus duct were taken into account.…”
Section: Power Lossesmentioning
confidence: 99%
See 1 more Smart Citation
“…In cases such as twin lines with opposing currents, the error in resistance will be the same as δP%, because power losses are proportional to resistance. The calculations were performed for 4 sets of (R/δ, d/R) ratios: (1, 2), (1,4), (4, 2), (4,4). In all the cases, typical variants of currents in the bus duct were taken into account.…”
Section: Power Lossesmentioning
confidence: 99%
“…The solution was expressed as infinite series with coefficients, which have to be found via successive approximations. Later Arnold [4] used this result as well as some others to obtain formulae for the proximity factor defined as AC resistance to DC resistance for round parallel conductors in single and three-phase cases. There were many approaches with semi-analytical solutions, where fields are expressed as infinite series, yet the coefficients in the series have to be determined numerically by solving a system of linear algebraic equations.…”
Section: Introductionmentioning
confidence: 99%
“…This must be incorporated by another subdivision of the skins into arc segments (see Figure 7). Arnold [31] yields an analytical approach to calculate the proximity effect. Based on the error which occurs from the calculation of the subconductor impedances Z mm and Z mn , the segmentation of the skins can be defined.…”
Section: Frequency-dependent Segmentation Of Conductorsmentioning
confidence: 99%
“…For rectangles and semiellipses, we find peaks in the loss curves at low frequencies for large b/d. This is due to the proximity effect [9] of the current between neighboring bumps. In fact, referring to Fig.…”
Section: Power Lossmentioning
confidence: 99%