1991
DOI: 10.1021/ic00007a036
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Proton spin-lattice NMR relaxation studies of hydride carbonyl clusters: a method to evaluate distances involving hydrido ligands

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Cited by 16 publications
(6 citation statements)
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“…1 H relaxation basically depends on dipole−dipole interaction and provides spatial relationship. In organometallic chemistry short relaxation times of hydrogens bound to a metal can be a signature of the occurrence of a nonclassical dihydrogen ligand in the absence of a significant dipolar contribution of the metal itself. , Differential dipolar contributions to the hydrido ligand relaxation provided structural assignments, distances in good agreement with the neutron diffraction data, and proved the occurrence of hydrogen or dihydrogen bond interactions in solution …”
Section: Introductionmentioning
confidence: 69%
“…1 H relaxation basically depends on dipole−dipole interaction and provides spatial relationship. In organometallic chemistry short relaxation times of hydrogens bound to a metal can be a signature of the occurrence of a nonclassical dihydrogen ligand in the absence of a significant dipolar contribution of the metal itself. , Differential dipolar contributions to the hydrido ligand relaxation provided structural assignments, distances in good agreement with the neutron diffraction data, and proved the occurrence of hydrogen or dihydrogen bond interactions in solution …”
Section: Introductionmentioning
confidence: 69%
“…Further an accurate determination may be obtained by the isolation of the selective H,H dipolar term. In our system this goal is easily achieved by the comparison of the T 1 values of the two isotopomers, H(μ-H)Os 3 (CO) 10 (HNC(CH 3 ) 2 ) and H(μ-H)Os 3 (CO) 10 (DNC(CH 3 ) 2 ). …”
Section: Resultsmentioning
confidence: 99%
“…On these grounds, it was possible to evaluate the dipolar contribution of the imine proton to the relaxation of the terminal and bridging hydrides. From these values actual H−H distances can be estimated according to , where the molecular reorientational time τ c is equal to 0.618/ω 0 (ω 0 = 2π400 × 10 6 rad s -1 ), i.e., 2.45 × 10 -10 rad s -1 . The resulting r H,H distances were 2.1 ± 0.1 Å and 2.7 ± 0.1 Å for the terminal and the bridging hydride, respectively.…”
Section: Resultsmentioning
confidence: 99%