2014
DOI: 10.1016/j.aim.2013.12.001
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Properly immersed submanifolds in complete Riemannian manifolds

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Cited by 18 publications
(11 citation statements)
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“…• Biharmonic submanifolds with finite total mean curvature in a Riemannian manifold of non-positive sectional curvature [148]. • Biharmonic properly immersed submanifolds in a complete Riemannian manifold with non-positive sectional curvature whose sectional curvature has polynomial growth bound of order less than 2 from below [139]. • Complete biharmonic submanifolds with finite bi-energy and energy in a non-positively curved Riemannian manifold [149].…”
Section: Recent Developments On Generalized Biharmonic Conjecturementioning
confidence: 99%
“…• Biharmonic submanifolds with finite total mean curvature in a Riemannian manifold of non-positive sectional curvature [148]. • Biharmonic properly immersed submanifolds in a complete Riemannian manifold with non-positive sectional curvature whose sectional curvature has polynomial growth bound of order less than 2 from below [139]. • Complete biharmonic submanifolds with finite bi-energy and energy in a non-positively curved Riemannian manifold [149].…”
Section: Recent Developments On Generalized Biharmonic Conjecturementioning
confidence: 99%
“…For p-biharmonic submanifolds, it is easy to see that we can get same (similar) results as in the results of biharmonic submanifolds in many cases. (For example, Corollary 3.6, 3.9 in [12], and so on.) In fact, the same argument as in Proof of Theorem 1.3 shows the following result.…”
Section: Appendixmentioning
confidence: 99%
“…We will prove the theorem by a contradiction argument. Here we follow Maeta's( [27]) argument by choosing new test functions. Suppose that H(x 0 ) = 0 for some…”
Section: Proof Of Theorem 11mentioning
confidence: 99%
“…Remark 1.1. When p = 2, theorem 1.1 was proved by Maeta(see [27]). Our proof follows his argument by using the second derivatives' test to our new test functions.…”
Section: Introductionmentioning
confidence: 97%
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