1992
DOI: 10.1016/0166-8641(92)90007-m
|View full text |Cite
|
Sign up to set email alerts
|

Products of spaces of ordinal numbers

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1
1

Citation Types

0
6
0
1

Year Published

1997
1997
2017
2017

Publication Types

Select...
5
2

Relationship

3
4

Authors

Journals

citations
Cited by 28 publications
(7 citation statements)
references
References 2 publications
0
6
0
1
Order By: Relevance
“…From this and Corollary 3.3 from [7], the next follows immediately. Notice that we also obtain that the product of two semi-proximal spaces that are Fréchet may have their product not semi-proximal; this answers Problem 14 in [8].…”
Section: Lemma Let a Bmentioning
confidence: 61%
See 1 more Smart Citation
“…From this and Corollary 3.3 from [7], the next follows immediately. Notice that we also obtain that the product of two semi-proximal spaces that are Fréchet may have their product not semi-proximal; this answers Problem 14 in [8].…”
Section: Lemma Let a Bmentioning
confidence: 61%
“…In [7], normality-type properties of products of subspaces of ordinals were studied. In Corollary 3.3 of that paper, the authors prove that a product A × B, where A, B ⊂ ω 1 , is normal if and only if either one of A or B is not stationary or A ∩ B is stationary.…”
Section: Theoremmentioning
confidence: 99%
“…Moreover, using elementary submodels, it is proved in [4] that products of arbitrary many ordinals are mildly normal. In [6], it is proved that for A, B ⊆ ω 1 , A × B is normal if and only if A or B is non-stationary or A ∩ B is stationary in ω 1 . Since there are disjoint stationary sets A and B in ω 1 , there is a non-normal product A × B of two subspaces of ω 1 .…”
Section: Introductionmentioning
confidence: 98%
“…• ω 1 × (ω 1 + 1) is countably paracompact but not normal, • if A and B are disjoint stationary sets in ω 1 , then A ×B is neither normal nor countably paracompact [11], • ω ω 1 is normal, but ω 1 ω 1 is not normal [3], • κ ω 1 is countably (para)compact for every κ,…”
Section: Introductionmentioning
confidence: 99%