1990
DOI: 10.1016/0040-9383(90)90017-e
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Producing reducible 3-manifolds by surgery on a knot

Abstract: IT HAS long been conjectured that surgery on a knot in S3 yields a reducible 3-manifold if and only if the knot is cabled, with the cabling annulus part of the reducing sphere (cf. [7.8, 9, 10, 111). One may regard the Poenaru conjecture (solved in [S]) as a special case of the above. More generally, one can ask when surgery on a knot in an arbitary 3-manifold A4 produces a reducible 3-manifold M'. But this problem is too complex, since, dually, it asks which knots in which manifolds arise from surgery on redu… Show more

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Cited by 123 publications
(111 citation statements)
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“…We remark that in general M (γ) may not be a solid torus for any γ since we are performing Dehn filling on the outer torus. Because of that, the powerful Reducible Surgery Theorem of Scharlemann [Sch,Theorem 6.1] does not apply to this situation.…”
Section: Introductionmentioning
confidence: 99%
“…We remark that in general M (γ) may not be a solid torus for any γ since we are performing Dehn filling on the outer torus. Because of that, the powerful Reducible Surgery Theorem of Scharlemann [Sch,Theorem 6.1] does not apply to this situation.…”
Section: Introductionmentioning
confidence: 99%
“…The Cabling Conjecture is known to hold in many special cases [2], [8], [9], [12], [13], [17], [19].…”
Section: Introductionmentioning
confidence: 99%
“…We first assume that X is compact. If dX is incompressible in X-K, the result is part of [8,Theorem 6.1]. In general, choose B = (JB¡ to be the union of some disjoint compressing disks of dX in X -K, so that after cutting X along B, the new manifold Xx = X -lnt(N(B)) has boundary incompressible in Xx -K. By the hypothesis, dX has a compressing disk D such that dD does not bound a disk in X -K. Among all such compressing disks, we choose one, say Dx, that is transverse to B and minimizes \DX nB\.…”
Section: Introductionmentioning
confidence: 99%