“…Rescaling π 3 , the inclusion hierarchy yields π 3 = [0, 0, 0, 0, 4, 0, 0, 2, 0, 0, 0, 0, 1, 0, 0, 2, 0, 0, 0, 0] π 2 = [0, 4, 6, 2, 0, 1, 0, 2, 3, 4, 0, 1, 2, 0, 2] π 1 = [12, 6, 10, 12, 8, 6] = 2 [6, 3,5,6,4,3] For example, π 2 ({2, 6}), ninth entry from the left, has a weight of 3, since {2, 6} is contained in both R 3 and R 4 . And π 1 = 54π.…”